(X-4)(x+2)=x^2-7x+17

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Solution for (X-4)(x+2)=x^2-7x+17 equation: 



(X-4)(X+2)=X^2-7X+17

We move all terms to the left:

(X-4)(X+2)-(X^2-7X+17)=0

We get rid of parentheses

-X^2+(X-4)(X+2)+7X-17=0

We multiply parentheses ..

-X^2+(+X^2+2X-4X-8)+7X-17=0

We add all the numbers together, and all the variables

-1X^2+(+X^2+2X-4X-8)+7X-17=0

We get rid of parentheses

-1X^2+X^2+2X-4X+7X-8-17=0

We add all the numbers together, and all the variables

5X-25=0

We move all terms containing X to the left, all other terms to the right

5X=25

X=25/5

X=5

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